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(8×3)^2+25x<\ 606
24^2+25x<\ 606
576+25x<\ 606
25x<\ 606-576
25x<\ 30
x<\ 30/25
x<\ 6/5
x aparţine (-infinit, 6/5]
Răspuns:
(2³·3)²+25·x ≤ 606
(8·3)²+25x ≤ 606
24²+25x ≤ 606
576+25x ≤ 606
25x ≤ 606-576
25x ≤ 30
x ≤ 30:25
x ≤ 1,2
x∈ {-∞ ; 1,2}