Răspuns:
m=200g=0,2kg
y=0,2sin(π/4*t+π/16)m
Viteza unghiulara
ω=4
Frecventa
ω=2πf
f=ω/2π=(π/4)/2π=1/8 s⁻¹
Perioada
T=1/f=8s
Viteza
v=0,2*π/4cos(π/4t+π/16)
a= -0,2*(π/4)²sin(π/4*t+π/16)
Energia maxima
Emax=mω²A²/2 unde
ω=π/4
A=amplitudinea=0,2m
m=0,2kg
Emax=0,2*(π/4)²*0,2/2=0,2*0,1*π²/16=0,02π²/16=2π²/100*16=
π²/800
plicație:
