a)
sodiul reactioneaza cu apa cu formare de NaOH si H2 si consuma apa disn sistem...
92 g a g b g n moli
2Na + 2H2O --> 2NaOH + H2
2x23 2x18 2x40 1
=> a = 92x2x18/2x23
= 72 g apa consumata
=> b = 92x2x40/2x23 = 160 g NaOH format
m.apa ramasa = m.apa - a
= 300 - 72 = 228 g
ms.formata = b + m.apa.ramasa
= 160+228 = 388 g
stim ca c% = mdx100/ms
= bx100/388 = 160x100/388 = 41,25%
b)
=> n = 92x1/2x23 = 2 moli H2
V = niux22,4 = 44,8 L H2
N.molecule = niuxN.A. = 2x6,022x10la23
= 1,2044x10la24 molecule H2
N.atomi = niux2xN.A.
= 2x2x6,022x10la23 = 2,4088x10la23 atomi H
