Răspuns:
diferenta sumei procentelor de masa si 100 indica %H=3,44
transform procentele de masa in numar de moli si impart prin cel mai mic numar
nC= 62,06/12=5,17 molC---> 5,17/1,15= 4,5C
nN= 16,10/14= 1,15 molN----> 1,15/1,15=1 N
nO=18,40/16=1,15molO------> 1,15/1,15=1-O
nH=3,44..................................3,44/1,15= 3H
DAR, cum sa- specificat ca sunt 6H .,trebuie inmultit cu 2 toate rezultatle
C9H6N2O2
M,C=12g/mol M,N=14g/mol M,O=16g/mol M,H=1g/mol
