Va rog mult ............

Răspuns:
x2-27\(x-3)(x+3)-(5\x+3-(x2+3x\(x-3)(x+3)-x2+x-3x-3\(x+3)(x-3)=
x2-27-5x-15-x2-3x-x2+2x-3=
+6x-45