Răspuns:
DATE necesare
M,KOH= 56g/mol
M,K2SO4=174g/mol
M,Cu(OH)2=98g/mol
-calculez md, masa de KOH dizolvata in solutie
c=mdx100/ms
md= 125x16/100g= 20g
ecuatia reactiei chimice:
2mol.. 1mol 1mol sau, in grame
2KOH + CuSO4------> K2SO4 +Cu(OH)2↓
2x56g............................174g..............98g
20......................................x........................y
x= 20x174/2x56 gK2SO4=........................CALCULEAZA
y= 20x98/2x56 gCu(OH)2=..............................calculeaza
Explicație:
