solutia finala trebuie sa fie
ms = 200 g sol. , c = 20%
aplicam regula dreptunghiului:
c1 = 36% -----------------------> 20-10 = 10 parti sol. c1
c.final= 20%
c2 = 10% -----------------------> 36-20 = 16 parti sol c2
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total = 10+ 16 = 26 parti sol de 20%
daca la 26 parti ... 10 parti sol c1 ...... 16 parti sol c2
200 g a g sol c1 b g sol c2
= 76,92 g sol c1 = 123,1 sol c2
=> ms1 = 76,92 g
ro = ms/Vs => Vs = ms/ro
=> Vs.c1 = 76,92/1,18 = 65,2 cm3
=> ms2 = 123,1 g
ro = ms/Vs => Vs = ms/ro
=> Vs.c1 = 123,1/1,05 = 117,24 cm3
