[tex]\displaystyle 33\sqrt{3}-\left(\frac{15}{2\sqrt{3}}+\frac{12}{5\sqrt{2}}\right)\cdot10\sqrt{6}-\left(\frac{3}{2\sqrt{8}}-\frac{5}{3\sqrt{12}}\right)\cdot12\sqrt{6}+8\sqrt{32}=\\ \\ =33\sqrt{3}-\frac{75\sqrt{2}+24\sqrt{3}}{10\sqrt{6}}\cdot 10\sqrt{6}-\left(\frac{3}{4\sqrt{2}}-\frac{5}{6\sqrt{3}}\right)\cdot 12\sqrt{6}+32\sqrt{2}=\\ \\=33\sqrt{3}-(75\sqrt{2}+24\sqrt{3})-\frac{9\sqrt{3}-10\sqrt{2}}{12\sqrt{6}}\cdot 12\sqrt{6}+32\sqrt{2}=[/tex]
[tex]\displaystyle =33\sqrt{3}-75\sqrt{2}-24\sqrt{3}-(9\sqrt{3}-10\sqrt{2})+32\sqrt{2}=\\ \\=33\sqrt{3}-75\sqrt{2}-24\sqrt{3}-9\sqrt{3}+10\sqrt{2}+32\sqrt{2}=\mathbf{-33\sqrt{2}}[/tex]
