Exercitiul 10 b o sa dau coroana

ex 10)
b)
[tex] {9}^{29} = ( {3}^{2} ) {}^{29} = {3}^{58} [/tex]
[tex] {27}^{19} = ({3}^{3}) {}^{19} = {3}^{57} [/tex]
[tex] {3}^{58} > {3}^{57} = > {9}^{29} > {27}^{19} [/tex]