Răspuns:
Explicație pas cu pas:
a) (2²⁰¹⁷-2²⁰¹⁶-2²⁰¹⁵):2⁵:16⁵⁰²+16⁰·1¹⁶=2²⁰¹⁵·(2²-2¹-1):2⁵:(2⁴)⁵⁰²+1·1=2²⁰¹⁵⁻⁵⁻²⁰⁰⁸+1= 2²+1=4+1=5
b) (2017⁰+27²⁷:9⁴⁰)⁵⁰:32²⁰=(1+(3³)²⁷:(3²)⁴⁰)⁵⁰:(2⁵)²⁰=(1+3⁸¹:3⁸⁰)⁵⁰:2¹⁰⁰=(1+3)⁵⁰:2¹⁰⁰=(2²)⁵⁰:2¹⁰⁰=2¹⁰⁰:2¹⁰⁰=1
[tex]c)~2^{2^{3}}:4^{3}+3^{2^{2}}:(2^{6}-6^{2}-36^{0})=2^{8}:(2^{2})^{3}+3^{4}:(64-36-1)=\\=2^{8}:2^{6}+3^{4}:27=2^{8-6}+3^{4}:3^{3}=2^{2}+3^{1}=4+3=7\\[/tex]
