Răspuns:
-calculez masa de Al pur, din puritate
p=m,px100/mi-----> m,p= 8x70/100g=5,6g
-deduc masele de HCl si H2 din ecuatia chimica, stiid, M,HCl=36,5g/mol M,H2=2g/mol, M,Al= 27g/mol
6mol.......2mol........1mol sau, ingrame
6HCl + 2Al ----> Al2Cl3 +3 H2
6x36,5g....2x27g................3x2g
x..................5,6g....................y=
x= 6x36,5x5,6/2,x27g=22,4gHCl
y= 5,6x3x2/2x27g=0,62gH2
-CALCULEZ masa solutiei de acid, care contine md=22,4gHCl
c= mdx100/ms----> ms= 22,4x100/25g=........calculeaza
Explicație: