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daca a+b=60, b+c= 78 si c+a =306, calculeaza ( a+b+c):3​

Răspuns :

a+b + b + c + c + a = 306 (impartim ambii termeni la 6)

(2a+2b+2c)/6=51

2(a+b+c)/6=51 (simplificam cu 2 fractia din stanga)

(a+b+c)/3=51