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aflati diagonala unui patrat cu perimetrul de 108​

Răspuns :

P = 4l = 108 => l = 108 : 4 = 27

d = l√2 => d = 27√2

 

[tex]\displaystyle\bf\\P~=108~cm\\\\L=\frac{P}{4}=\frac{108}{4}=\boxed{\bf27~cm}\\\\D=L\sqrt{2}=\boxed{\bf27\sqrt{2}~cm}[/tex]