1 intreg 5/6 = (1×6+5)/6=11/6
1 intreg 8/9= (1×9+8)/9= 17/9
a) x=11/6=1,8(3)
y=17/9=1,(8)
deci se vede ca x>y
b)y:(x^2-y)=17/9:[(11/6)^2 - 11/6]=
17/9:[121/36-11/6] amplificãm pe 11/6 cu 6
17/9:[121/36-66/36]=
17/9:55/36= 17/9×36/55= (17×4)/55= 68/55