Răspuns:
Explicație pas cu pas:
a)
(a^12 + a^20)^0 : (a^8 : a^8) = 1 : 1 = 1
[tex]a = [ {a}^{5} \times {a}^{7} + ( {a}^{1})^{20}]^{0} \div [( {a}^{2})^4 \div ({a}^{4})^{2}] \\ a = ( {a}^{5 + 7} + {a}^{1 \times 20} ) ^{0} \div ( {a}^{2 \times 4} \div {a}^{4 \times 2}) \\ a = ( {a}^{12} + {a}^{20} )^{0} \div ( {a}^{8} \div {a}^{8} ) \\ a = 1 \div 1 \\ \boxed{a = 1}[/tex]
Formule aplicate
[tex] {a}^{m} \times {a}^{n} = {a}^{m + n} \\ ( {a}^{m} )^{n} = {a}^{m \times n} \\ {a}^{0} = 1, a \not = 0 \\ {a}^{m} \div {a}^{m} = 1[/tex]
