Ducem inaltimea DK, DK⊥AB
m(<D)=m(<C)=135°
m(<A)=m(<B)=(360°-2*135°)/2=(360-270)/2=90/2=45°
sin45°=DK/AD⇒DK=AD*sin45°=4√2*√2/2=4(cm)=>INALTIMEA
ctg45°=AK/DK⇒AK=DK*ctg45°⇒AK=4*1=4(cm)
AB=2*AK+4=2*4+4=12(cm)
P=4√2*2+12+4=(8√2+16) cm
ΔODC~ΔAOB⇒AO/OC=AB/CD⇒
⇒AO/OC=12/4=3
Bafta!
