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x+y+z=150 x, y, z d.p 2 5 8 x=? Y=? Z=?

Răspuns :

[tex] \frac{x}{2} = \frac{y}{5} = \frac{z}{8} = k[/tex]

x=2k

y=5k

z=8k

x+y+z=150 => 2k+5k+8k=150

15k=150

k=150÷15

k=10

x=2×10=20

y=5×10=50

z=8×10=80

[tex]x + y + z = 150[/tex]

[tex] \frac{x}{2} = \frac{y}{5} = \frac{z}{8} = k[/tex]

[tex] = > x = 2k[/tex]

[tex] = > y = 5k[/tex]

[tex] = > z = 8k[/tex]

Inlocuim in prima relatie si obtinem:

2k+5k+8k=150

15k=150

k=150:15

k=10

x= 2k=2•10=20

y= 5k=5•10=50

z=8k=8•10=80

Raspuns: x=20

y=50

z=80