determina termenul necunoscut

Răspuns:
Explicație pas cu pas:
a) 8/10-1/10=x+5/10 x=7/10-5/10=2/10=1/5 ; b) 2-1-y=o,5 ; y=1-0,5 ; y=0,5
a)
[tex] \frac{8}{10} - ( \frac{5}{10} + x) = \frac{1}{10} [/tex]
[tex] \frac{5}{10 } + x = \frac{8}{10} - \frac{1}{10} [/tex]
[tex] \frac{5}{10} + x = \frac{7}{10} [/tex]
[tex]x = \frac{7}{10} - \frac{5}{10} = \frac{2}{10} [/tex]
b)
[tex]2 - \frac{2}{2} - y = \frac{1}{2} [/tex]
[tex] \frac{2}{1} - \frac{2}{2} - y = \frac{1}{2} [/tex]
[tex] \frac{4}{2} - \frac{2}{2} - y = \frac{1}{2} [/tex]
[tex] \frac{2}{2} - y = \frac{1}{2} [/tex]
[tex]y = \frac{2}{2} - \frac{1}{2} [/tex]
[tex]y = \frac{1}{2} [/tex]
SAU(mai usor)
[tex]2 - \frac{2}{2} - y = \frac{1}{2} [/tex]
[tex]2 - 1 - y = \frac{1}{2} [/tex]
[tex]1 - y = \frac{1}{2} [/tex]
[tex]1 - y = 0.5[/tex]
[tex]y = 1 - 0.[/tex]
[tex]y = 0.5 = \frac{1}{2} [/tex]