BaSO4
M=137 +32 + 64=233-----> 233g/moli
233g BaSO4-------137 g Ba-------32 g S --------64 g O
100 g-------------------x------------------y------------------z
x=100.137 : 233=58,80% Ba
y=100.32 : 233=13,73 % S
z=100.64 : 233=27,46 % O
NaCl
M=23 +35,5=58,5------>58,5g/moli
58,5g NaCl---------23 g Na---------35,5 gCl
100g------------------xg Na--------------yg Cl
x=100.23 :58,5=39.31 % Na
y=100.35,5 : 58,5=60,68 % Cl
Al2O3
M=2.27 + 3.16=102-----> 102g/moli
102g Al2 O3--------54 g Al--------48 g O
100g---------------------x-------------------y
x=100.54 : 102=52,94 % Al
y=100.48 : 102=47,06 % O
Ca(NO3)2
M=40 + 2.14 +6.16=164------>164g/moli
164 g Ca(NO3)2----------40g Ca ------28g N--------96gO
100g----------------------------x-----------------y-------------------z
x=100.40 :164=24,39% Ca
y=100.28 : 164=17,07% N
z=100.96 :164=58,53 % O
Ca3(PO4)2
M=3.40 +2.31 +8.16=310 ------> 310g/moli
310g Ca3(PO4)2-------120 g Ca ------62 g P---------128 g O
100g--------------------------x----------------y-------------------z
x=100.120 : 310=38,7% Ca
y=100.62 :310=20% P
z=100.128 :310=41,3 % O
Mg3(PO4)2
M=3.24 + 2.31 +8.16=260------>260g/moli
260g Mg3(PO4)2---------72g Mg--------62g P---------128 g
100 g----------------------------x------------------y--------------z
x=100.72 :260=
y=100.62:260=
z=100.128 : 260=
Comp. proc. prin raport de masa
BaSO4
r.m.= 137 : 32 : 64
137+32+64=233
se face la fel cu prima metoda
NaCl
r.m.=23 :35,5
23+35,5=58,5
se face la fel cu prima metoda
Al2o3
r.m.=54: 48=9: 8 [s-a simplif. cu 8]
9+ 8 =17
17 g Al2 O3-------9gAl----------8 g O
100 g------------------x-----------------y
x=100 .9 : 17=52,94 % Al
y=100.8 : 17=47,06 % O
[pe celelalte te rog sa le lucrezi singur , dupa modele]
