Vreau și eu rezolvarea exercitiului 3,va rog!

1,12 = a/50
112/100 = a/50
112/100 = 2a/100
112 = 2a
a = 56
4,24 = b/25
424/100 = b/25
424/100 = 4b/100
424 / 4b
b = 106
a+b = 56+106 = 162
3.
[tex]1.12 = \frac{a}{50} | \times 50 = > 50 \times 1.12 = 50 \times \frac{a}{50} = > 56 = 50 \times \frac{a}{50} = > 56 = a = > a = 56.[/tex]
[tex]4.24 = \frac{b}{25} | \times 25 = > 4.24 \times 25 = 25 \times \frac{b}{25} = > 106 = 25 \times \frac{b}{25} = > 106 = b = > b = 106[/tex]
[tex]a + b = 56 + 106 = 162[/tex]