cred ca este vorba de hidroxidul de calciu Ca(OH)2
M,=(40gCa+2x16,gO +2x1,gH)/MOL= 74g/mol\
1mol hidroxid...........74g
x................................740g
x=n=10mol Ca(OH)2
1mol Ca(OH)2........1molatomiCa.........2molatomiO.......2molatomiH
10mol...............x= 10molatomi Ca..y= 20molatmiO...Z= 20mol atomiH,
1mol atomi...........6,023X10²³atomi
10mol at Ca..................x= 6,023x10²⁴ at.Ca
1mol at O sau H............6,023X10²³atomi
20mol O sau H..................x= calculeaza !!!!!!
