Răspuns:
Explicație pas cu pas:
[tex]\displaystyle\int_0^1\dfrac{3x}{2x+3}dx=\dfrac{3}{2}\int_0^1\dfrac{2x+3-3}{2x+3}dx=\dfrac{3}{2}\int_0^1dx-\dfrac{3}{2}\int_0^1 \dfrac{3}{2x+3}dx=\\\dfrac{3}{2}x|_0^1-\dfrac{9}{4}\ln(2x+3)|_0^1=\dfrac{3}{2}-\dfrac{9}{4}\ln\dfrac{5}{3}[/tex]
