cine ma poate ajuta?Va roooooooog

3.9
Δl=0,5 cm=0,005 m
L=kΔl²/2=40*0,005²/2=20*0,000025=0,0005 J=0,5 mJ
4.0
Δl1=4 mm=0,004 m
Δl2= 4 cm=0,04 m
L1=kΔl1²/2=>k=2L1/Δl1²=2*0,02/0,004²=0,04/0,000016=2500 N/m
L2=kΔl2²/2=2500*0,04²/2=1250*0,0016=2 J