Ma ajuta si pe mine cineva ? Va rog ! urgent ! dau coroana

√5-x=3x-1 ( )²
5-x=9x²-6x+1
9x²-6x+1+x-5=0
9x²-5x-4=0
a=9; b=-5; c=-4
Δ=b²-4ac=(-5)²-4×9×(-4)=25+144=169 > 0
x₁₂=(-b±√Δ)/2a=(5±13)/18
x₁=18/18=1
x₂=-8/18=-4/9