1.
MnO2 (IV)
miu = 55+16x2 = 87 g/mol
%Mn = 55x100/87 = 63,22%
Mn2O7 (VII)
miu = 55x2+16x7 = 222 g/mol
%Mn = 55x2x100/222 = 49,55%
2.
nr. de moli = masa/miu = V/Vm , Vm = volumul molar = 22,4 L (c.n.)
=> ca m = Vxmiu/Vm ; miu(CO2) = 44 g/mol
a) 22,4 L => m = 22,4x44/22,4 = 44 g CO2
b) 2,24 L => m = 2,24x44/22,4 = 4,4 g CO2
c) 44,8 L => m = 44,8x44/22,4 = 88 g CO2
3.
2 acizi:
H2 + S => H2S
2H2 + O2 => 2H2O
2N2 + 5O2 = 2N2O5
N2O5 + H2O => 2HNO3
2 baze:
2H2 + O2 => 2H2O
2K + 2H2O => 2KOH + H2
Na + O2 => Na2O
Na2O + H2O => 2NaOH
