C6H5-CH2Cl , miu = 126,5 g/mol
C6H5-CHCl2 , miu = 161 g/mol
126,5 g Cl-benzil ............. 35,5 g Cl
ax126,5 g Cl-benzil .......... z g Cl
z = 35,5a
161 g Cl-benziliden ............. 71 g Cl
bx161 g Cl-benzil ................ t g Cl
t = 71b
ax126,5 + bx161 = 100
35,5a + 71b = 40 / : 35,5
=> a + 2b = 1,127 => a = 1,127-2b
=> 142,53 - 253b + 161b = 100
=> b = 0,46 g C6H5-CHCl2
=> a = 0,207 g C6H5-CH2Cl
=> a + b = 0,667 g amestec de cloruri
% C6H5-CHCl2 = 0,46x100/0,667 = 69%
