Bilele din urnă:
a) cazuri favorabile: 9
cazuri posibile: 36
[tex]P=\frac{9}{36}=\bf\frac{1}{4}\\[/tex]
b) cazuri favorabile: 1
cazuri posibile: 36
[tex]P=\frac{1}{36}\\\\[/tex]
c) cazuri favorabile: 9 + 6 = 15
cazuri posibile: 36
[tex]P=\frac{15}{36}=\bf\frac{5}{12}\\[/tex]
d) cazuri favorabile: 0
cazuri posibile: 36
[tex]P=\frac{0}{36}=\bf0\\[/tex]
e) cazuri favorabile: 36
cazuri posibile: 36
[tex]P=\frac{36}{36}=\bf 1\\[/tex]
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