Notăm cee trei numere cu a, b, c .
a = 60; 2b = 3c
[tex]\it m_a=\dfrac{a+b+c}{3}=100 \Rightarrow a+b+c=3\cdot100 \Rightarrow 60+b + c = 300\bigg|_{-60} \Rightarrow \\ \\ \\ \Rightarrow b+c=240\bigg|_{\cdot2} \Rightarrow 2b+2c=480 \Rightarrow 3c+2c=480 \Rightarrow 5c=480\bigg|_{:5} \Rightarrow \\ \\ \\ \Rightarrow c=96\\ \\ \\ 2b=3c \Rightarrow 2b=3\cdot96\bigg|_{:2} \Rightarrow b=3\cdot48 \Rightarrow b=144[/tex]
Numerele cerute sunt: a=60; b=144; c=96 .
