Răspuns:
a) (2/3)^2 • (2/3)^7 = (2/3)^2+7=(2/3)^9
b) (3/10)^3•(3/10)^10= (3/10)^3+10 =(3/10)^13
c) (11/5)^4•(11/5)^6= (11/5)^4+6= (11/5)^10
d) (3/4)^11:(3/4)^4= (3/4)^11-4=(3/4)^7
e) (8/3)^9:(8/3)^8=(8/3)^9-8=(8/3)^1=8/3
f) (13/17)^22:(13/17)^20=(13/17)^22-20=(13/17)^2
g)[(2/15)^5]^11= (2/15)^5•11=(2/15)^55
h)[(14/27)^6]^4=(14/27)^24
i) dacă este 0 la putere automat rezultatul va fi egal cu 1
^ - la putere
• - înmulțire
Succes! Sper că ai înțeles!!
