Calculați:
[tex]a)\:(\sqrt8+\sqrt{32})\sqrt2=(2\sqrt2+4\sqrt2)\sqrt2=6\sqrt2\sqrt2=6\times2=\bf12\\[/tex]
[tex]b)\:(\sqrt{27}-\sqrt{12})\sqrt3=(3\sqrt3-2\sqrt3)\sqrt3=\sqrt3\sqrt3=\bf3\\[/tex]
[tex]c)\:2\sqrt5(\sqrt{125}-3\sqrt5)=2\sqrt5(5\sqrt5-3\sqrt5)=2\sqrt5\times2\sqrt5=2\times5\times2=\bf20\\[/tex]
[tex]d)\:(4\sqrt{24}+2\sqrt{54})(-0,5\sqrt6)=(8\sqrt6+6\sqrt6)(-0,5\sqrt6)=14\sqrt6\times(-0,5\sqrt6)=14\times6\times(-0,5)=\bf-42\\[/tex]
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Despre scoaterea factorului de sub radical aici:
https://brainly.ro/tema/1959561
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