Sigur, să rezolvăm aceste calcule:
a)
- \(24,522 \div 22 = 1111\)
- \(480,000 \div 12 = 40,000\)
- \(500,606 \div 25 = 20,024.24\)
- \(6,780 \div 60 = 113\)
- \(768,645 \div 15 = 51,243\)
b)
- \(637 \div 35 = 18.2\)
- \(4,747 \div 47 = 101\)
- \(999,998 \div 99 = 10,101.01\)
- \(4,221 \div 21 = 201\)
- \(12,999,999 \div 99,999 = 130\)
c)
- \(3,003 \div 30 = 100.1\)
- \(30,030 \div 30 = 1,001\)
- \(550,550 \div 55 = 10,010\)
- \(879,423 \div 79 = 11,133\)
- \(79,300 \div 97 = 818.56\)
