Efectuați calculele:
[tex]a)\:(x+3)^2+(x+1)^2-(2x+1)(2x-1)=\\[/tex]
[tex]=x^2+6x+9+x^2+2x+1-4x^2+1=\\[/tex]
[tex]=-2x^2+8x+11\\[/tex]
[tex]b)\:(3-2x)^2-(2x+5)(2x-5)+(x-2)^2=\\[/tex]
[tex]=9-12x+4x^2-4x^2+25+x^2-4x+4=\\[/tex]
[tex]=x^2-16x+38\\[/tex]
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Pentru rezolvarea acestui exercițiu am folosit formulele de calcul prescurtat:
[tex]\bf\red{\boxed{(a+b)^2=a^2+2ab+b^2}}\\[/tex]
[tex]\bf\blue{\boxed{(a-b)^2=a^2-2ab+b^2}}\\[/tex]
[tex]\bf\orange{\boxed{(a+b)(a-b)=a^2-b^2}}\\[/tex]
Succes! ❀
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