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Rezolvați prin metoda reducerii sistemele:
a) (3(x+2y)-2(2x+y-3)+5=21 5(x-y+1)=4(x+y+2)-23 ;

b) (2(-x-y+3)-4(x-y+1)+8=32 2(x+y+4)=3(2x+2y-3)+21 ;

c) 3(x+y+3)+2(x-y-4)=x+3y+3 (4(x+y+1)=5(2x+y+2)+9 ;

Repede, va rog! dau coroana!​


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