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27 Rezolvați ecuațiile: a 2x(4+2√3)-√√3(5x+3√√3)=2√√3(3√√3 − x)+2(4x −9) ; b (√5−2√3).x+2x(√5 +√3)=√125+2x√√5; c 2-√√3+2x(2-√√3)= 4(x-√√3)+√√27; d x√2+1+√2+x(1+√√2)+x(3+2√√2) = 5(3+√√2)-2(3+2√2) √5−2+x(√5 − 2) = x(2 + √5) − (√5 + 2); † √√3(√√2x+1)+√√2(√3x + 1) = 2x(√√6 +1)−(√3-√2).​

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